WebQuest
Breaking the Language Barrier Using Polynomials
Process
The representative from the Factors is kind enough to remind you how to translate English into Factorian and vise-versa. She provides you with a convenient translation chart, as seen in Figure 1.
Figure 1. English-Factorian Translation Chart
English Factorian
A (x-1)(x+2)
B 2(x-2)(x-3)
C (2x+3)(x-1)
D (x-3)(x+9)
E (x-4)(x+7)
F (x-4)(x-7)
G (x+3)(x-6)
H (x-5)(x+5)
I (x+5)(x-6)
J (x-6)(x-1)
K (x+1)(x-1)
L (x+3)(x-8)
M (x-8)(x+9)
N (x+4)(x-3)
O (x-2)(x-4)
P (x+7)(x-6)
Q (x-7)(x+6)
R (x-4)(x-6)
S (x-4)(7x-6)
T (3x+7)(9x+8)
U (x+1)(x+2)
V (4x-5)(x-1)
W (x+3)(x-7)
X (x+8)(x-9)
Y 2(x-9)(x+9)
Z (x+5)(x+6)
So for example if we wish to write the letter A in Factorian, we would simply consult Figure 1, and see that A corresponds to the Factorian letter (x-1)(x+2).
The Factorian representative then informs you that if we wish to write the letter A in Polynomian, we must first convert A into its Factorian form (x-1)(x+2), and then expand
(x-1)(x+2)=x(x+2)-1(x+2)
=x^2+2x-x-2
=x^2+x-2,
yielding the Polynomian form of A. So A in Polynomian would appear as the letter x^2+x-2.
The Factorian representative then asks you to write the word HELLO in Polynomian, just to make sure you have understood her instructions. You then proceed:
H=(x-5)(x+5)
=x(x+5)-5(x+5)
=x^2+5x-5x-25
=x^2-25
E=(x-4)(x+7)
=x(x+7)-4(x+7)
=x^2+7x-4x-28
=x^2+3x-28
L=(x+3)(x-8)
=x(x-8)+3(x-8)
=x^2-8x+3x-24
=x^2-5x-24
L=(x+3)(x-8)
=x(x-8)+3(x-8)
=x^2-8x+3x-24
=x^2-5x-24
O=(x-2)(x-4)
=x(x-4)-2(x-4)
=x^2-4x-2x+8
=x^2-6x+8
English Factorian Polynomian
H (x-5)(x+5) x^2-25
E (x-4)(x+7) x^2+3x-28
L (x+3)(x-8) x^2-5x-24
L (x+3)(x-8) x^2-5x-24
O (x-2)(x-4) x^2-6x+8
So HELLO=(x^2-25)(x^2+3x-28)(x^2-5x-24)(x^2-5x-24)(x^2-6x+8)
The Factorian representative approves, as you have correctly translated the word HELLO from English to Polynomian.
You are now ready to send a message to the Polynomes!!!
The Public URL for this WebQuest:
http://zunal.com/webquest.php?w=16627
WebQuest Hits: 17,900
Save WebQuest as PDF